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1、CHAPTER6 DiscreteProbabilityDistributionstoaccompanyIntroductiontoBusinessStatisticsfourthedition,byRonaldM.WeiersPresentationbyPriscillaChaffe-StengelDonaldN.Stengel?2002TheWadsworthGroupChapter6-LearningObjectivesDistinguishbetweendiscreteandcontinuousran
2、domvariables.DifferentiatebetweenthebinomialandthePoissondiscreteprobabilitydistributionsandtheirapplications.Constructaprobabilitydistributionforadiscreterandomvariable,determineitsmeanandvariance,andspecifytheprobabilitythatadiscreterandomvariablewillhave
3、agivenvalueorvalueinagivenrange.?2002TheWadsworthGroupChapter6-KeyTermsRandomvariablesDiscreteContinuousBernoulliprocessProbabilitydistributionsBinomialdistributionPoissondistribution?2002TheWadsworthGroupDiscretevsContinuousVariablesDiscreteVariables:Canta
4、keononlycertainvaluesalonganintervalthenumberofsalesmadeinaweekthevolumeofmilkboughtatastorethenumberofdefectivepartsContinuousVariables:Cantakeonanyvalueatanypointalonganintervalthedepthatwhichadrillingteamstrikesoilthevolumeofmilkproducedbyacowtheproporti
5、onofdefectiveparts?2002TheWadsworthGroupDescribingtheDistributionforaDiscreteRandomVariableTheprobabilitydistributionforadiscreterandomvariabledefinestheprobabilityofadiscretevaluex.Mean:μ=E(x)=Variance:s2=E[(x–μ)2]=?2002TheWadsworthGroupTheBernoulliProcess
6、, CharacteristicsTherearetwoormoreconsecutivetrials.Ineachtrial,therearejusttwopossibleoutcomes.Thetrialsarestatisticallyindependent.Theprobabilityofsuccessremainsconstanttrial-to-trial.?2002TheWadsworthGroupTheBinomialDistributionThebinomialprobabilitydist
7、ributiondefinestheprobabilityofexactlyxsuccessesinntrialsoftheBernoulliprocess.foreachvalueofx.Mean:μ=E(x)=npVariance:s2=E[(x–μ)2]=np(1–p)?2002TheWadsworthGroupTheBinomialDistribution, AnExampleWorkedbyEquationProblem6.23:AstudybytheInternationalCoffeeAssoc
8、iationfoundthat52%oftheU.S.populationaged10andoverdrinkcoffee.Forarandomlyselectedgroupof4individuals,whatistheprobabilitythat3ofthemarecoffeedrinkers?NumberProportionCoffeedrinkers(x)3.52Noncoffeedrin
