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1、剛剛學windows編程，所以想寫學習筆記，這是一個簡單的Socket程序例子，開發(fā)環(huán)境是vc6：首先是TCPserver端：[cpp]?viewplaincopy1.#include?"stdafx.h"??2.#include???3.#include???4.??5.#pragma?comment(lib,"ws2_32.lib")??6.??7.int?main(int?argc,?char*?argv[])??8.{??9.????//初始化WSA??10.????WORD?sockVersion?=?MAKEWORD(2,2);?
2、?11.????WSADATA?wsaData;??12.????if(WSAStartup(sockVersion,?&wsaData)!=0)??13.????{??14.????????return?0;??15.????}??16.??17.????//創(chuàng)建套接字??18.????SOCKET?slisten?=?socket(AF_INET,?SOCK_STREAM,?IPPROTO_TCP);??19.????if(slisten?==?INVALID_SOCKET)??20.????{??21.????????printf("socket?error?!");??22.
3、????????return?0;??23.????}??24.??25.????//綁定IP和端口??26.????sockaddr_in?sin;??27.????sin.sin_family?=?AF_INET;??28.????sin.sin_port?=?htons(8888);??29.????sin.sin_addr.S_un.S_addr?=?INADDR_ANY;???30.????if(bind(slisten,?(LPSOCKADDR)&sin,?sizeof(sin))?==?SOCKET_ERROR)??31.????{??32.????????printf
4、("bind?error?!");??33.????}??34.??1.????//開始監(jiān)聽??2.????if(listen(slisten,?5)?==?SOCKET_ERROR)??3.????{??4.????????printf("listen?error?!");??5.????????return?0;??6.????}??7.??8.????//循環(huán)接收數(shù)據(jù)??9.????SOCKET?sClient;??10.????sockaddr_in?remoteAddr;??11.????int?nAddrlen?=?sizeof(remoteAddr);??12.????
5、char?revData[255];???13.????while?(true)??14.????{??15.????????printf("等待連接...");??16.????????sClient?=?accept(slisten,?(SOCKADDR?*)&remoteAddr,?&nAddrlen);??17.????????if(sClient?==?INVALID_SOCKET)??18.????????{??19.????????????printf("accept?error?!");??20.????????????continue;??21.????????
6、}??22.????????printf("接受到一個連接：%s?r",?inet_ntoa(remoteAddr.sin_addr));??23.??????????24.????????//接收數(shù)據(jù)??25.????????int?ret?=?recv(sClient,?revData,?255,?0);?????????26.????????if(ret?>?0)??27.????????{??28.????????????revData[ret]?=?0x00;??29.????????????printf(revData);??30.????????}??31.??3
7、2.????????//發(fā)送數(shù)據(jù)??33.????????char?*?sendData?=?"你好，TCP客戶端！";??34.????????send(sClient,?sendData,?strlen(sendData),?0);??35.????????closesocket(sClient);??36.????}??37.??????38.????closesocket(slisten);??39.????WSACleanup();??40.
