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1、2第一章1-1:3已知:V=72cmm=129.1gms=121.5gGs=2.70mm?129.1121.5?s則:w???6.3%m121.5sm129.13???g?g?*1017.9?KNm/v72ms121.53V???45cms?s2.73V?VV??7245??27cmVsmsat?wVV?ms1.0*27121.5?3???g?g?g?*10?20.6KNm/satsatVV723???????20.61010.6??KNm/satwms121.53??g?*1016.9?KNm/dV72則????????satd1-2:3已知:Gs=2.72設Vs=1cm3??2.72/
2、gcmsmg?2.72sms2.723???g?g?*1016?KNm/ddV1.7mVs?V?w2.720.7*1?3???g?g?*10?20.1KNm/V1.73則???????20.11010.1??KNm/w當S?75%時,rm??VS?1.0*0.7*75%?0.525gwwVrm0.525ww???19.3%m2.72smmws?0.5252.72?3???gg??*1019.1?KNm/V1.71-3:347m??V?1.70*10*8*10?13.6*10kgsd77m?mw?13.6*10*20%?2.72*10kgws77mmsw?13.6*10?2.72*103Vm
3、??85000挖3?1.92*101-4:甲:I?w?w?402515??pLP設V?1則sm???*V2.7gsssmg??2.7*30%0.81w又因為S?100%rmw?V??0.81V?wmmsw?2.70.81?3????1.94/gcmVV??10.81sw3????g19.4KNm/ms2.73????1.48/gcmdVV?1.81sw3????g14.8KNm/ddVve??0.81Vs乙:I?w?w?8pLp設V?1則m??V?2.68gssssm?mw?2.68*22%?0.4796gws3則V?0.4796cmVmmsw?2.680.4796?3????2.14/g
4、cmVV??10.4796sV3???g?2.14*10?21.4KNm/ms2.683????1.84/gcmdVV?1.4796sw3???g?1.84*1018.4?KNm/ddVVe??0.4796Vs???????ee?II?甲乙d甲d乙甲乙p甲p乙則(1)、(4)正確1-5:G?sw??則d1?eG?2.7*1swe???1??10.59?1.70dwG22%*2.7sS????185%re0.59所以該料場的土料不適合筑壩,建議翻曬,使其含水率降低。1-6:()????ddmindmaxD?r()????dmaxdmind33式中Dr=0.7??1.96/gcm??1.46/
5、gcmdmaxdmin3則可得:??1.78/gcmd1-7:設S=1,則V??Shhs則壓縮后:mwm??VG2.7hm??mw2.7*28%h則Vh??2.7*28%ssswsw?wV?V?2.7*28%h??h1.95則h?1.11cmsw?h?2.01.110.89??cmVVh0.89VVe????0.8Vh1.11s1-8:ww?p4525?甲:I???1.33流塑狀態(tài)Lww??4025Lpww?p2025?乙:I????0.33堅硬(半固態(tài))Lww??4025LpI?w?w?15屬于粉質粘土(中液限粘質土)pLp乙土較適合作天然地基1-9:Ip甲5336?A???0.310.
6、75?屬非活性粘土甲P550.002甲Ip乙7035?A???1.31.25?屬活性粘土乙P270.002乙乙土活動性高,可能為伊利石,及少量的高嶺石,工程性質乙土的可能較第二章2-1解:根據(jù)滲流連續(xù)原理,流經(jīng)三種土樣的滲透速度v應相等,即vvv??ABC??hh?hABC根據(jù)達西定律,得:RRR??ABCLLLABC??hhh:?:??1:2:4ABC又??h??h??h?35cmABC??h?5cmh,??10cmh,??20cmABC?hA?3V??k1*10cms/ALA3V?VA**t=0.1cm加水2-2解:G?12.701?si???1.076cr1??e10.582-3解:
7、?h20(1)土樣單位體積所受的滲透力j?1*r?1*9.8*?6.53NwL30G?12.721?s(2)i???1.055cr1??e10.63?h20i???0.667L30?ii?則土體處于穩(wěn)定狀態(tài),不會發(fā)生流土現(xiàn)象crh(3)當ii?時,會發(fā)生流土破壞,即?i時crcrLh?Li*?30*1.05531.65?cmcr水頭差值為32cm時就可使土樣發(fā)生流土破壞2-4解:hh?AC(1)h?6,mh?7.5,mh