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1、第二章習題部分解答－第90頁1.解：由矩估計法：8?1?a?X?74.002??xi?8i?1?821???Sx2??610?6??(?74.002)2i??8i?12n28??66?SS????610?6.85710?n??181第二章習題部分解答－第90頁2（1）解：由矩估計法：????A11'?2(???x)???EX?xdx??1?20?3????3????A11（2）'1???1??EX?x(??1)xdx???1?0??221?????1??（3）x??1???1???e2?xdx??????1?12?1?2x??1?n??11???
2、?e2?xdx2?A??X2??2?2??22i12?1?2ni?1222?AS??????(???)?2??222??????S1??????S2N1NN(?1)1（4）Ax1??????i?1NN2?N?21??（5）1??1?A????xxdx?1?0??1?2???()??1?22k?2（6）A????kk(?1)?(1??)?1k?2?2????3.解:設A??{?0},X表示A出現(xiàn)的次數(shù)，2()xa?01?PA()?P{??0}??e2dx??2????aa0?P{?}???(a)?p?0.7,11?pa?0.7,??0.5254.解
3、：n????(1)(1)()L????cxii?1nln()L???[ln???lnc?(??1)ln]xii?1nn?ln()L??1???[?lnc?ln]xii??nlnc?lnx?0???ii??11nn??n?lnxi?nlnci?1n??1(2)()Lx????ii?1nln()Lx???[ln??(??1)ln]ii?1n?ln()L?111??[?ln]0xi???i?1?22??2n??n2(?ln)xii?1n11(3)()L????ni?1??ln()Ln????ln?ln()Ln????0?????11??,,?,????
4、,??nn1nn()L()???????????0,other0,other11??,()LL??()nn()n??()n???()nn(4)()LC????xi?xi(1?)Nx?iNi?1nxiln()L???[lnCN?xiln??(N?xi)ln(1??)]i?1nn??xii()N?x?ln()L?ii??11???0????1?x??Nn121??2()xi?(5)()Le???2?i?1??2n2()x??iln()L????[ln2??]2i?12?n22??ln()Ln??2?2(xx???)?2(???)ii???[04???
5、2??i?122n??12?????i?42ni?1ncc??(1)(6)()L????cxii?1nln()L????[lncc?ln?(c?1)ln]xii?1?ln()L?nc???0不能解出?，所以由???ncc??(1)L()????c?xin,??1,,?i?1LL()??(?)????(1)(1)n2xi?2(7)()Lx???（i?1)?(1??)i?1nln()L???[2ln??(xii?2)ln(1??)ln(?x?1)]i?1n?xni?2?ln()Ln?22i?1??]0????????1??n(8)()L?????()
6、xi(2)??(xi??1)(13)???(xi2)??n0(2)(13)?nn12??i?1??ln()L??2??0????45.解：??~U(,0)n11(1)()L??,????,??,0n?1n?i?1??()??max???,()LL?()?(1)?~U(,2)??n11(2)()L????n,???1,,?n?2?i?1?????()n1n?min?,()LL??(),?,,??222nn6.解：1??x?(1)()L??????fx(,)eiiii??112x,,xx??x???x??x1n(1)()i(1)i?()nnin11?
7、?
8、xi???
9、?x()k??x()l?(n?2)iL()???ei?1ek?1li??1nn22??,n為奇n?1()?2????????時L()達到最大值nn?()(?1)22,n為偶??27.解：1111?~U(??,??),????,,????1n2222n1L()????1,11i?1(???)(??)22???(1)()n???or???2所以不唯一。8.解nn(1)()L?????e???()xti?0,ln()?L??[ln?(xt)ln]?i0i?1i?1n?ln()L?1nn???(xti?0)??0??n????i?1xt?
10、0?xi?nt0i?1nn(2)()Lt???e???()xti0,ln()Lt??[ln??(x?t)]?00i0i?1i?1?ln(
